Finished all chapters and definitions. I need to add subsections and see if there's any theorems or definitions in the appendicies that are worth adding to this as well.
This commit is contained in:
@@ -3,13 +3,13 @@
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\begin{definition}
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\hfill\\
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Let $A$ be an $m \times n$ matrix. Any one of the following three operations on the rows [columns] of $A$ is called an \textbf{elementary row [column] operation}:
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\begin{enumerate}
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\item interchanging any two rows [columns] of $A$;
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\item multiplying any row [column] of $A$ by a nonzero scalar;
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\item adding any scalar multiple of a row [column] of $A$ to another row [column].
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\end{enumerate}
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Any of these three operations are called an \textbf{elementary operation}. Elementary operations are of \textbf{type 1}, \textbf{type 2}, or \textbf{type 3} depending on whether they are obtained by (1), (2), or (3).
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\end{definition}
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@@ -26,4 +26,4 @@
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\begin{theorem}
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\hfill\\
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Elementary matrices are invertible, and the inverse of an elementary matrix is an elementary matrix of the same type.
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\end{theorem}
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\end{theorem}
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@@ -18,12 +18,12 @@
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\begin{definition}
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\hfill\\
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A matrix is said to be in \textbf{reduced row echelon form} if the following three conditions are satisfied.
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\begin{enumerate}
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\item Any row containing a nonzero entry precedes any row in which all the entries are zero (if any).
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\item The first nonzero entry in each row is the only nonzero entry in its column.
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\item The first nonzero entry in each row is 1 and it occurs in a column to the right of the first nonzero entry in the preceding row.
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\end{enumerate}
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\end{definition}
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@@ -31,10 +31,10 @@
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\begin{definition}
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\hfill\\
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The following procedure for reducing an augmented matrix to reduced row echelon form is called \textbf{Gaussian elimination}. It consists of two separate parts.
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\begin{enumerate}
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\item In the \textit{forward pass}, the augmented matrix is transformed into an upper triangular matrix in which the first nonzero entry of each row is $1$, and it occurs in a column to the right of the first nonzero entry in the preceding row.
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\item In the \textit{backward pass} or \textit{back-substitution}, the upper triangular matrix is transformed into reduced row echelon form by making the first nonzero entry of each row the only nonzero entry of its column.
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\end{enumerate}
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\end{definition}
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@@ -46,30 +46,30 @@
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\begin{definition}
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A solution to a system of equations of the form
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\[s = s_0 + t_1u_1 + t_2u_2 + \dots +t_{n-r}u_{n-r},\]
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where $r$ is the number of nonzero solutions in $A'$ ($r \leq m$), is called a \textbf{general solution} of the system $Ax = b$. It expresses an arbitrary solution $s$ of $Ax = b$ in terms of $n - r$ parameters.
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\end{definition}
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\begin{theorem}
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\hfill\\
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Let $Ax = b$ be a system of $r$ nonzero equations in $n$ unknowns. Suppose that $\rank{A} = \rank{A|b}$ and that $(A|b)$ is in reduced row echelon form. Then
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\begin{enumerate}
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\item $\rank{A} = r$.
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\item If the general solution obtained by the procedure above is of the form
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\[s = s_0 + t_1u_1 + t_2u_2 + \dots + t_{n-r}u_{n-r},\]
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then $\{u_1, u_2, \dots, u_{n-r}\}$ is a basis for the solution set of the corresponding homogeneous system, and $s_0$ is a solution to the original system.
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\[s = s_0 + t_1u_1 + t_2u_2 + \dots + t_{n-r}u_{n-r},\]
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then $\{u_1, u_2, \dots, u_{n-r}\}$ is a basis for the solution set of the corresponding homogeneous system, and $s_0$ is a solution to the original system.
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\end{enumerate}
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\end{theorem}
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\begin{theorem}
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\hfill\\
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Let $A$ be an $m \times n$ matrix of rank $r$, where $r > 0$, and let $B$ be the reduced row echelon form of $A$. Then
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\begin{enumerate}
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\item The number of nonzero rows in $B$ is $r$.
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\item For each $i = 1, 2, \dots, r$, there is a column $b_{j_i}$ of $B$ such that $b_{j_i} = e_i$.
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@@ -81,4 +81,4 @@
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\begin{corollary}
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\hfill\\
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The reduced row echelon form of a matrix is unique.
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\end{corollary}
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\end{corollary}
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@@ -2,8 +2,8 @@
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\begin{definition}
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\hfill\\
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The system of equations
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The system of equations
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\begin{equation}\label{eq:S}
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\tag{S}
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\begin{split}
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@@ -13,47 +13,47 @@
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a_{m1}x_1 + a_{m2}x_2 + \dots + a_{mn}x_n = b_m,
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\end{split}
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\end{equation}
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where $a_{ij}$ and $b_i$ ($1 \leq i \leq m$ and $1 \leq j \leq n$) are scalars in a field $\F$ and $x_1, x_2, \dots, x_n$ are $n$ variables taking values in $\F$, is a called a \textbf{system of $m$ linear equations in $n$ unknowns over the field $\F$}.
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The $m \times n$ matrix
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The $m \times n$ matrix
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\[\begin{pmatrix}
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a_{11} & a_{12} & \dots & a_{1n} \\
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a_{21} & a_{22} & \dots & a_{2n} \\
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\vdots & \vdots & & \vdots \\
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a_{m1} & a_{m2} & \dots & a_{mn}
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\end{pmatrix}\]
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a_{11} & a_{12} & \dots & a_{1n} \\
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a_{21} & a_{22} & \dots & a_{2n} \\
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\vdots & \vdots & & \vdots \\
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a_{m1} & a_{m2} & \dots & a_{mn}
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\end{pmatrix}\]
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is called the \textbf{coefficient matrix} of the system \eqref{eq:S}.
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If we let
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\[x = \begin{pmatrix}
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x_1 \\ x_2 \\ \vdots \\ x_n
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\end{pmatrix}\ \ \text{and}\ \ b = \begin{pmatrix}
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b_1 \\ b_2 \\ \vdots \\ b_m
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\end{pmatrix},\]
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x_1 \\ x_2 \\ \vdots \\ x_n
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\end{pmatrix}\ \ \text{and}\ \ b = \begin{pmatrix}
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b_1 \\ b_2 \\ \vdots \\ b_m
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\end{pmatrix},\]
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then the system \eqref{eq:S} may be rewritten as a single matrix equation
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\[Ax = b.\]
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To exploit the results that we have developed, we often consider a system of linear equations as a single matrix equation.
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A \textbf{solution} to the system \eqref{eq:S} is an $n$-tuple
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\[s = \begin{pmatrix}
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s_1 \\ s_2 \\ \vdots \\ s_n
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\end{pmatrix} \in \F^n\]
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s_1 \\ s_2 \\ \vdots \\ s_n
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\end{pmatrix} \in \F^n\]
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such that $As = b$. The set of all solutions to the system \eqref{eq:S} is called the \textbf{solution set} of the system. System \eqref{eq:S} is called \textbf{consistent} if its solution set is nonempty; otherwise it is called \textbf{inconsistent}.
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\end{definition}
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\begin{definition}
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\hfill\\
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A system $Ax = b$ of $m$ linear equations in $n$ unknowns is said to be \textbf{homogeneous} if $b = 0$. Otherwise the system is said to be \textbf{nonhomogeneous}.\\
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Any homogeneous system has at least one solution, namely, the zero vector.
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\end{definition}
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@@ -75,7 +75,7 @@
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\begin{theorem}
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\hfill\\
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Let $K$ be the solution set of a system of linear equations $Ax = b$, and let $\mathsf{K}_\mathsf{H}$ be the solution set of the corresponding homogeneous system $Ax = 0$. Then for any solution $s$ to $Ax = b$
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\[K = \{s\} + \mathsf{K}_\mathsf{H} = \{s + k: k \in \mathsf{K}_\mathsf{H}\}.\]
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\end{theorem}
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@@ -96,33 +96,33 @@
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\begin{definition}
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Consider a system of linear equations
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\[\begin{split}
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a_{11}p_1 + a_{12}p_2 + \dots + a_{1m}p_m = p_1 \\
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a_{21}p_1 + a_{22}p_2 + \dots + a_{2m}p_m = p_2 \\
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\dots \\
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a_{n1}p_1 + a_{n2}p_2 + \dots + a_{nm}p_m = p_m \\
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\end{split}\]
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This system can be written as $Ap = p$, where
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a_{11}p_1 + a_{12}p_2 + \dots + a_{1m}p_m = p_1 \\
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a_{21}p_1 + a_{22}p_2 + \dots + a_{2m}p_m = p_2 \\
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\dots \\
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a_{n1}p_1 + a_{n2}p_2 + \dots + a_{nm}p_m = p_m \\
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\end{split}\]
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This system can be written as $Ap = p$, where
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\[p = \begin{pmatrix}
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p_1 \\ p_2 \\ \vdots \\ p_m
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\end{pmatrix}\]
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and $A$ is the coefficient matrix of the system. In this context, $A$ is called the \textbf{input-ouput (or consumption) matrix}, and $Ap = p$ is called the \textbf{equilibrium condition}.
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For vectors $b = (b_1, b_2, \dots, b_n)$ and $c = (c_1, c_2, \dots, c_n)$ in $\R^n$, we use the notation $b \geq c$ [$b > c$] to mean $b_i \geq c_i$ [$b_i > c_i$] for all $i$. The vector $b$ is called \textbf{nonnegative [positive]} if $b \geq 0$ [$b > 0$].
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p_1 \\ p_2 \\ \vdots \\ p_m
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\end{pmatrix}\]
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and $A$ is the coefficient matrix of the system. In this context, $A$ is called the \textbf{input-output (or consumption) matrix}, and $Ap = p$ is called the \textbf{equilibrium condition}.
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For vectors $b = (b_1, b_2, \dots, b_n)$ and $c = (c_1, c_2, \dots, c_n)$ in $\R^n$, we use the notation $b \geq c$ [$b > c$] to mean $b_i \geq c_i$ [$b_i > c_i$] for all $i$. The vector $b$ is called \textbf{non-negative [positive]} if $b \geq 0$ [$b > 0$].
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\end{definition}
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\begin{theorem}
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\hfill\\
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Let $A$ be an $n \times n$ input-output matrix having the form
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\[A = \begin{pmatrix}
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B & C \\
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D & E
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\end{pmatrix},\]
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where $D$ is a $1 \times (n -1)$ positive vector and $C$ is an $(n-1)\times 1$ positive vector. Then $(I -A)x = 0$ has a one-dimensional solution set that is generated by a nonnegative vector.
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\end{theorem}
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B & C \\
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D & E
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\end{pmatrix},\]
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where $D$ is a $1 \times (n -1)$ positive vector and $C$ is an $(n-1)\times 1$ positive vector. Then $(I -A)x = 0$ has a one-dimensional solution set that is generated by a non-negative vector.
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\end{theorem}
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@@ -13,7 +13,7 @@
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\begin{theorem}
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\hfill\\
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Let $A$ be an $m \times n$ matrix. if $P$ and $Q$ are invertible $m \times m$ and $n \times n$ matrices, respectively, then
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\begin{enumerate}
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\item $\rank{AQ} = \rank{A}$,
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\item $\rank{PA} = \rank{A}$,\\ and therefore
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@@ -34,30 +34,30 @@
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\begin{theorem}
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\hfill\\
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Let $A$ be an $m \times n$ matrix of rank $r$. Then $r \leq m$, $r \leq n$, and, by means of a finite number of elementary row and column operations, $A$ can be transformed into the matrix
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\[D = \begin{pmatrix}
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I_r & O_1 \\
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O_2 & O_3
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\end{pmatrix}\]
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I_r & O_1 \\
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O_2 & O_3
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\end{pmatrix}\]
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where $O_1$, $O_2$ and $O_3$ are the zero matrices. Thus $D_{ii} = 1$ for $i \leq r$ and $D_{ij} = 0$ otherwise.
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\end{theorem}
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\begin{corollary}
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\hfill\\
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Let $A$ be an $m \times n$ matrix of rank $r$. Then there exist invertible matrices $B$ and $C$ of sizes $m \times m$ and $n \times n$, respectively, such that $D=BAC$, where
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\[D = \begin{pmatrix}
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I_r & O_1 \\
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O_2 & O_3
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\end{pmatrix}\]
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I_r & O_1 \\
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O_2 & O_3
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\end{pmatrix}\]
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is the $m \times n$ matrix in which $O_1$, $O_2$, and $O_3$ are zero matrices.
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\end{corollary}
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\begin{corollary}
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\hfill\\
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Let $A$ be an $m \times n$ matrix. Then
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\begin{enumerate}
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\item $\rank{A^t} = \rank{A}$.
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\item The rank of any matrix equals the maximum number of its linearly independent rows; that is, the rank of a matrix is the dimension of the subspace generated by its rows.
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@@ -73,7 +73,7 @@
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\begin{theorem}
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\hfill\\
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Let $T: V \to W$ and $U: W \to Z$ be linear transformations on finite-dimensional vector spaces $V$, $W$, and $Z$, and let $A$ and $B$ be matrices such that the product $AB$ is defined. Then
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\begin{enumerate}
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\item $\rank{UT} \leq \rank{U}$.
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\item $\rank{UT} \leq \rank{T}$.
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@@ -85,4 +85,4 @@
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\begin{definition}
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\hfill\\
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Let $A$ and $B$ be $m \times n$ and $m \times p$ matrices, respectively. By the \textbf{augmented matrix} $(A|B)$, we mean the $m \times (n \times p)$ matrix $(A\ B)$, that is, the matrix whose first $n$ columns are the columns of $A$, and whose last $p$ columns are the columns of $B$.
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\end{definition}
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\end{definition}
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