Created the Abstract Algebra theorems and definitions cheat sheet

part-4/chapters/chapter-22/chapter-22.tex

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+\chapter{Finite Fields}
+\subimport{./}{classification-of-finite-fields.tex}
+\subimport{./}{structure-of-finite-fields.tex}
+\subimport{./}{subfields-of-a-finite-field.tex}

part-4/chapters/chapter-22/classification-of-finite-fields.tex

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+\section{Classification of Finite Fields}
+
+\begin{theorem}[Classification of Finite Fields]
+	For each prime $p$ and each positive integer $n$, there is, up to isomorphism, a unique finite field of order $p^n$.
+\end{theorem}

part-4/chapters/chapter-22/structure-of-finite-fields.tex

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+\section{Structure of Finite Fields}
+
+\begin{theorem}[Structure of Finite Fields]
+	As a group under addition, $\gf(p^n)$ is isomorphic to
+	\[ \underbrace{\Z_p \oplus \Z_p \oplus \dots \oplus \Z_p}_\text{$n$ factors} \]
+	As a group under multiplication, the set of nonzero elements of $\gf(p^n)$ is isomorphic to $\Z_{p^n-1}$ (and is, therefore, cyclic).
+\end{theorem}
+
+\begin{remark}
+	Because there is only one field for each prime-power $p^n$, we may unambiguously denote it by $\gf(p^n)$, in honor of Galois, and call it the \textit{Galois field of order $p^n$}.
+\end{remark}
+
+\begin{corollary}
+	\[ [\gf(p^n):\gf(p)]=n \]
+\end{corollary}
+
+\begin{corollary}[$\mathbf{\gf(p^n)}$ Contains an Element of Degree $\mathbf{n}$]
+	Let $a$ be a generator of the group of nonzero elements of $\gf(p^n)$ under multiplication. Then $a$ is algebraic over $\gf(p)$ of degree $n$.
+\end{corollary}

part-4/chapters/chapter-22/subfields-of-a-finite-field.tex

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+\section{Subfields of a Finite Field}
+
+\begin{theorem}[Subfields of a Finite Field]
+	For each divisor $m$ of $n$, $\gf(p^n)$ has a unique subfield of order $p^m$. Moreover, these are the only subfields of $\gf(p^n)$.
+\end{theorem}