Created the Abstract Algebra theorems and definitions cheat sheet

This commit is contained in:
2024-01-09 11:30:56 -07:00
commit e8692b7dea
141 changed files with 2141 additions and 0 deletions
@@ -0,0 +1,4 @@
\chapter{Vector Spaces}
\subimport{./}{definition-and-examples.tex}
\subimport{./}{subspaces.tex}
\subimport{./}{linear-independence.tex}
@@ -0,0 +1,15 @@
\section{Definition and Examples}
\begin{definition}[Vector Space]
A set $V$ is said to be a \textit{vector space} over a field $\F$ if $V$ is an Abelian group under addition (denoted by $+$) and, if for each $a \in \F$ and $v \in V$, there is an element $av \in V$ such that the following conditions hold for all $a,b \in \F$ and all $u,v \in V$.
\begin{enumerate}
\item $a(v + u) = av + au$
\item $(a + b)v = av + bv$
\item $a(bv)=(ab)v$
\item $1v=v$
\end{enumerate}
\end{definition}
\begin{remark}
The members of a vector space are called \textit{vectors}. The members of the field are called \textit{scalars}. The operation that combines a scalar $a$ and a vector $v$ to form the vector $av$ is called \textit{scalar multiplication}. In general, we will denote vectors by letters from the end of the alphabet, such as $u,v,w$, and scalars by letters from the beginning of the alphabet, such as $a,b,c$.
\end{remark}
@@ -0,0 +1,19 @@
\section{Linear Independence}
\begin{definition}[Linearly Dependent, Linearly Independent]
A set $S$ of vectors is said to be \textit{linearly dependent} over a field $\F$ if there are vectors $v_1,v_2,\dots,v_n$ from $S$ and elements $a_1,a_2,\dots,a_n$ from $\F$, not all zero, such that $a_1v_1+a_2v_2+\dots+a_nv_n = 0$. A set of vectors that is not linearly dependent over $\F$ is called \textit{linearly independent} over $\F$.
\end{definition}
\begin{definition}[Basis]
Let $V$ be a vector space over $\F$. A subset $B$ of $V$ is called a \textit{basis} for $V$ if $B$ is linearly independent over $\F$ and every element of $V$ is a linear combination of elements of $B$.
\end{definition}
\begin{theorem}[Invariance of Basis Size]
If $\{u_1,u_2,\dots,u_m\}$ and $\{w_1,w_2,\dots,w_n\}$ are both bases of a vector space $V$ over a field $\F$, then $m=n$.
\end{theorem}
\begin{definition}[Dimension]
A vector space that has a basis consisting of $n$ elements is said to have \textit{dimension $n$}. For completeness, the trivial vector space $\{0\}$ is said to be spanned by the empty set and to have dimension 0.
\noindent A vector space that has a finite basis is called \textit{finite dimensional}; otherwise, it is called \textit{infinite dimensional}.
\end{definition}
+5
View File
@@ -0,0 +1,5 @@
\section{Subspaces}
\begin{definition}[Subspace]
Let $V$ be a vector space over a field $\F$ and let $U$ be a subset of $V$. We say that $U$ is a \textit{subspace} of $V$ if $U$ is also a vector space over $\F$ under the operations of $V$.
\end{definition}